This is another question that’s helpful to draw. K is second, thanks to the local rule.
Here’s what things look like when H is in 7:
MG can only fit in 5 and 6. That leaves space for F to go in 1, and J goes in 3.
When H is in 1, we get this diagram:
MG only have space to go in 5 and 6 or 6 and 7. F has to go in 3, because F goes before J.
In both cases, F is before S. A is CORRECT.
The first scenario proves B-E wrong.
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