It’s easy to answer this question if you figured out the numerical distributions.
At least four people have to leave messages. One person could leave three messages, and three other people could leave a single message, for a total of six.
The four people that always have to be in are P, T, H and L. They could be the four who leave messages. Here’s one possible scenario, just as an example:
We can’t have less than four people, because no one is allowed to leave more than three messages.
This analysis eliminates A, B, C and E. We need L, T, H and at least four people.
D is CORRECT.
If G is in, then everyone leaves one message. Here’s a working scenario where G is in:
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ken says
Probably late to the party but wouldn’t the answer be “E” because it is at least 4 people? I think it is a typo on this page.
TutorRosalie (LSATHacks) says
It isn’t a typo, D is the correct answer. Answer Choice E must be true because P, T, H, and L must have left messages. That’s four people who must have left messages, and if you take a look at the setup, you’ll see that it’s not possible to have only three people or less leave messages.
On the other hand, Answer Choice D does not have to be true. It could be that each of the six people only left one message each, such as “FPTLHG”.