(I’m reproducing the diagrams from the setup)
We’re told that four of the scenarios work, and only 1 doesn’t work. We should start with the longest string of variables: it’s the one most likely to violate a rule. E is CORRECT. If P is in, you can’t have K.
Many people think A can’t be true. But there’s no reason we can’t have T and K together. K being out means that T is in. So they can’t both be out. But they can both be in. K being in is not a sufficient condition for T being out.
None of the other answer choices have any rule violations. It’s also important to see if some variables being out cause other variables to be in. There’s only one pair of variables like that in this game: T and K. We always need one of them in. But B, C and D all do have either K or T.
So since those answer choices don’t violate any rules, and they all have T or K, they all work.
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MemberJaime says
How can TK be together? PT 36, Game 1, Q3.
If no T then K. If no K then T. That doesn’t compute TK.
FounderGraeme Blake says
Imagine this: you must have either a cat or a dog. So no cat, therefore dog. No dog, therefore cat.
But nowhere did I say you can’t have both! The rule just says you need at least one, and could have both.
Not both is: T –> no K
No T –> K is totally different. Hope that helps :)