A is CORRECT. M always goes with F. If M is with I, that means FM goes on the middle shelf.
In the setup, we saw that placing FM on the middle shelf determined everything:
This is what the diagram looks like if FM are on the bottom shelf instead:
If FM are on the bottom shelf, this game is almost impossible to lock down. There’s one more book to place: the 8th book can go on shelf three or four.
None of the remaining answers deal with this. Answers B, C and E place one of the random variables, G and H. That really doesn’t do much in this game.
K and G (answer B) and H and O (answer E) could both go together on either the top or the middle shelf. They’re very easy to move around, if F and M are on the bottom shelf.
If F, H and M are all on the bottom (D), we still get to decide whether we want to put a fourth book on the bottom, or put a third book on the middle shelf.
The same is true of C. If you put L and F together, they go on the bottom. M goes there too, with F. You still get to decide whether to put a fourth book with them, or a third book on the middle shelf instead.
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Member[email protected] says
Could you please explain what the question is asking?
TutorLucas (LSAT Hacks) says
The question is asking you to determine which answer choice would produce a gameboard that is “fully determined”, meaning a gameboard where every position can only be filled by one variable or, in this case, one set of variables, i.e. the top shelf, middle shelf, and bottom shelf would have no “either/or” options, each shelf could only be filled by one variable or one set of variables.