You can use both diagrams from the setup to eliminate answers. Here they are again:
T can never be first, so A is wrong.
B has three T’s in a row, which violates rule 2.
C is CORRECT. You can see it in the second diagram. Just make the final piece M.
D is wrong because it doesn’t have two T’s in a row. This violates rule 2.
E doesn’t work on either diagram. In the first, T is fourth but not fifth. In the second, the fourth piece is M, not T.
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Member[email protected] says
Could you please explain why A (T cannot be in A) is wrong?
TutorLucas (LSAT Hacks) says
T cannot be first because according to the rules, no traditional piece is performed until Wayne performs at least one modern piece. So, the earliest T can go is second.