LSAT 69, Logic Game 4, Question 23, LSATHacks

K has to be alone for this question.

R and T are the only groups where K can be alone. H is already in group S.

Remember that, along with K, one of F or G must be alone.

So, two groups, R and T. K goes in one, and one of F/G in the other.

Let’s try putting K in group T.

We have to place one of F/G in the other group. It’s got to be F, because of rule 1. If K is in T, F must go in R:

L and G are left, we can put them in group S. This diagram works:

Now let’s try putting K in group R:

F or G must go in T. It doesn’t matter which one. L and the other F/G go in S:

That diagram works too. So either K or F can be in group R, when K is alone.

B is CORRECT.