LG Game 3 Question 14 Explanation, by LSATHacks
If F is assigned to boat 2 then we can use the scenario we drew for the main setup.
F causes G to be in 2. We need an adult in boat 1, so H goes there. V and W can’t both go in 1, so one of them has to go in the free space in boat 2. That leaves Y and the other of V and W to go in boat 1.
This is a could be true question. None of answer choices A through D could be true.
A is wrong because Y has to be in boat 1 and F has to be in boat 2.
B is wrong because G has to be in boat 2 and H has to be in boat 1.
C is wrong because G and Y have to be in different boats.
D is wrong. V and W cannot be together in boat 1 and there is no room for them to be together in boat 2.
E is CORRECT. X and Z are interchangeable so Z could go in boat 1 with Y.
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