LSAT 20, Logic Game 3, Question 17, LSATHacks

The first and fourth beads are purple, the second and fifth are yellow so that means that the third and sixth must be red.

We’ve got nine beads. We need to fit all the colors in. Right now we’ve only got purple, yellow and red. We need green and orange. We can’t put orange in slot 7 beside red.  So we have to put orange in slot 8 and green in slot 7.

This is a could be true question.

A is wrong because the seventh bead can’t be orange; it would be beside red.

B is wrong because the eighth bead has to be orange. We need at least one orange in the row. And orange can only go in 8.

C is wrong for the same reason as B. We need orange in spot 8.

D is wrong because since we need orange in spot 8. So we can’t have an R beside orange in spot 9.

E could be true. We’ve already got all of our eight colors in spots 2-9. So 9 could be yellow as it doesn’t violate any rules. E is CORRECT.

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