LSAT 21, Logic Game 1, Question 4, LSATHacks

If R is assigned to a triple, then the game becomes pretty restricted. There are two other students that go with R. K and P are always assigned to their own double. L can’t go with R either, so two second year students go with R.

The second year students can’t be in a single, do we need another double. L and the other second year student go there. It looks like this.

A must be false because Lee is assigned to a double in this setup.

B must be false because R and L can’t go together. Therefore, L has to go in a double with one second year student. The other two second years go in a triple with R.

C is CORRECT. There are no singles. There is only a triple and two doubles.

D is wrong because there are no singles. (Second year students can’t be assigned to singles.)

E is wrong because we can’t have more than two singles, ever.

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