LSAT 21, Logic Game 1, Question 5, LSATHacks

This is a local rule question. It is worth drawing. We have T and V in two separate doubles.

K and P are in a double; this is always true.

That’s six people. So the only remaining thing we can have is a single. It looks like this.

A must be true:  one room is a single. A is CORRECT.

We can tell all the remaining answer choices are wrong just by looking at it our diagram. There are no other possibilities.

B is wrong because we can’t have two singles

C is wrong because we have three doubles, not two.

D and E are wrong because we have no triples at all.

---