LSAT 22, Logic Game 4, Question 23, LSATHacks

We need G in the front of the team 1. We could put H in the front of team 2 and put Q in the middle of team 1. Then we could put K and P in the second team. N or L would go in the third spot of team 1. This is the same diagram from the setup.

Is there any other way of doing it?  We’d have to leave H out, because if H goes on team 2, everything else falls into place. H can’t go in team one because G is in the only spot where H is permitted.

If H isn’t in, every other variable must be in. L can’t go in team 2. So the four people left that can be placed on team 2 would be three out of N, P, K and Q.

That doesn’t work. P can’t go with Q. N can’t go with P or K. No three of those people can go together.

This scenario is the only one that works:  H has to be in.

A is wrong because H has to be in 2, not 1.

B is wrong because K has to be in 2, not 1.

C is wrong because K and P have to be in 2, not 1.

D is wrong because L and N can’t be in team 1 together. There is only space for one of them.

E is CORRECT. We always have Q and we could have L.

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