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LSAT Explanations › Preptest 23 › LSAT Preptest 23 | Logic Games Explanations › Question 15

LSAT 23, Logic Game 3, Question 15, LSATHacks

LSAT 23 Explanations

LG Game 3 Question 15 Explanation, by LSATHacks

Franklin and Marquez are together. We have to put them on team 1. If we put them on team 2 that would mean J would be in team 1. And that would trigger the last rule, and the scenarios we saw in questions 13 and 14.

So F and M are on team 1, and J is on team 2. R and S can’t go on team 1, because M can’t go with them. That’s five total variables. Only N and O are left to fill the last spot on team 1.

LSAT Preptest 23, Game 3, Question 15, Diagram 15

A is wrong because J has to go on team 2.

B is wrong because R would be with M if R went on team 1.

C is CORRECT. We could put S on team 2. The only people S can’t go with are M and F.

D is wrong. We can’t put both N and O on team 1. There’s no space.

E is wrong. If we put both O and N on team 2 then we wouldn’t have anyone to put in the final spot on team 1.

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