LSAT 23, Logic Game 3, Question 17, LSATHacks

One of our diagrams from the last question proves that A can be true. A is CORRECT.

B can’t be true. If we put F on team 2 and we don’t have J on any team, that means that we have to have Marquez on team 1. (M is the only other anthropologist.)  S can’t go with M or F so that means that we don’t have S or J in either team. That’s too few people.

C can’t be true because if we put F and M on team 2 then J must go on 1 which forces R to go on 2.

D can’t be true because if J is on team 1 then R goes on team 2. That causes F to go onto team 2, because team 2 needs an anthropologist. So Franklin has to be on a team.

E can’t be true. If J is on team 1 then R and F are on team 2 and R is not able to go with N.

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