LSAT 24, Logic Game 2, Question 8, LSATHacks

If N is fifth we know that P will have to be second. (P is either second or fifth.)  M is first, because M goes before P.

Some people get tricked here. They think that L has to be in 3. But they’re getting it backwards.

If L goes in 3, N is in 5. But it doesn’t work in reverse. When N is in 5, L could be in 3 but doesn’t have to be.

So we have space to put Ken and Jamie in either 3 and 4 or 6 and 7.

A is wrong because Jamie can’t go in sixth. There’s no space to put Ken before Jamie.

B is wrong because P is in second. Ken can’t go there.

C is CORRECT. L could be fourth if we put O in third and K and J in 6 and 7.

D is wrong because M has to go before P. (P is in 2)

E is wrong. M has to go before P. So M has to go in 1, not O.

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