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LSAT Explanations › Preptest 27 › LSAT Preptest 27 Logic Games Explanations › Question 10

LSAT 27, Logic Game 2, Question 10, LSATHacks

LSAT 27 Explanations

LG Game 2 Question 10 Explanation, by LSATHacks

This question can take awhile. It goes faster if you write down who is left next to each answer choice.

A  We’ve used all our males and three of our snakes. We’ve got three female lizards and one female snake left to place. We have no restrictions on putting those anywhere. So we can just spread them across the last three spaces. For example:  3. two female lizards 4. one female snake 5. one female lizard.

B  We have used all the males. We have three female snakes and two female lizards left. As long as you don’t put female snakes bedie the male lizard then we’re fine. We can spread five reptiles across three spots. For example:  3. 2 female snakes. 4. one female snake. 5. two female lizards.

C  We have one lizard left and three snakes. Two males are left. As long as we keep the male lizards away from the female snakes we can easily split the four remaining reptiles across the last three spaces. For example:  3. One female lizard 4. One female snake 5. Two male snakes

D is CORRECT. It leaves us with three lizards and three snakes. There is no way to put these in the last three spots:  we can’t put lizards with snakes. Even if we put two lizards somewhere and two snakes somewhere, we’re still left with a lizard and a snake. It just won’t fit.

E  We have two lizards and four snakes. Both are males. This may look tricky but we can put things this way:  3. two female lizards  4. two male snakes 5. two female snakes. Everything fits.

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