Habitat 3 is empty. We don’t have snakes beside snakes.
We must put two snakes in 1 or 2 and two of them in 4 or 5, together. It looks like this:
The arrows show what is reversible. On one side of 3, we’ll have two snakes and a female lizard. On the other side, we’ll have two snakes and two female lizards.
The sides could be reversed, it makes no difference. Two of the snakes are male, and two are female. That also doesn’t matter.
The only thing we can’t do is have a male lizard because it would be beside female snakes.
A is CORRECT. There are no rules about even numbered habitats. We can switch our reptiles around and we can put snakes in even or odd numbered places, it doesn’t matter.
B is wrong. We can’t make any lizards male. They would be beside female snakes.
C is wrong. We can’t have snakes alone; we have to fit all four snakes in just two places. Otherwise we would have snakes beside habitats with other snakes.
D is wrong. Since snakes are apart, this also forces the lizards apart.
E has to be true and is therefore wrong. Because we have an odd number of lizards, there is always one that’s alone.
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