LSAT 29, Logic Game 4, Question 23, LSATHacks

LG Game 4 Question 23 Explanation, by LSATHacks

If O is not with P, then our diagram looks like this:

(Scroll down for diagrams + explanation)

H and one of N/S has to go with P, since no one else can. 

The other N/S, K, IL and G all go before P.

A is wrong because both O’s class and P’s class come after G. So G is fourth.

B is wrong because H has to go with P. 

C is wrong because G, O and P come after IL. So IL is third.

D is CORRECT. N could go with P, and P could go either fifth or sixth, depending on O.

E is wrong because one of N/S goes before K and the other goes with P. S is either first, fifth or sixth.

Hi, I'm Graeme Blake

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