We saw this scenario in the setup. Only when M is in 3 can we make cars 4 and 5 the same.
This is what happens if M is in 4:
No good, 4 and 5 are different.
Only the other scenario (M in 3) works:
We have to make the last two washes super to satisfy the local rule. They can’t be regular, because at least one wash needs to be super (rule 1). The first car becomes premium, because we always need exactly one p (rule 2).
B is CORRECT.
The diagram shows that the other answer choices can’t be true.
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