LG Game 4 Question 20 Explanation, by LSATHacks
We need three H’s. They can’t ever go on day 1, and for this question they can’t go on day 2. So they must go on days 3, 5 and 7.
There’s no other way to fit them in and keep them apart.
That means R can’t go on days 3, 5 and 7 (rule 5).
A is wrong because H has to be on day 3. M can’t go there.
B is CORRECT. There are no rules about S, so they could go on day 4.
C is wrong because H has to be on day 5. H and R can’t go together (rule 5).
D is wrong. We can’t fit three H’s if we put H on day 6. (no breed can go beside itself).
E is wrong. G can never go on day seven, because G goes on day 1 (rules 1 and 3).
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