LSAT 32, Logic Game 4, Question 22, LSATHacks

We already know H can’t be featured on day 1, and this question tells us they can’t go on day 7 either.

We still need to put in 3 H’s. The only way to keep them apart within those limits is to put them on days 2, 4 and 6.

When I was doing the game, I figured this out by making a quick sketch of seven lines and seeing how I could fit three H’s in spaces 2-6. Try it. It should only take 5-10 seconds.

Here’s what it looks like, with full details:

We know R can’t go opposite H. So I’ve drawn “not R” in those spaces. 

In 2 and 6, we also know that G and N respectively can’t go in those spots, because breeds can’t go twice in a row.

So N is featured on day 2, and G is featured on day 6.

Whenever you make a deduction, you should check if it is the right answer. Here, it is.

B is CORRECT. Days 2 and 6 have different breeds of puppy.

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