LG Game 3 Question 14 Explanation, by LSATHacks
R can’t be in H, because R is always with Q or S. And there aren’t two free spots for them in H, because T and U are there. So A is wrong.
S can be in row H in the first scenario. B is CORRECT.
C is wrong because in the first scenario S and Q are in different rows. In the second scenario Q and S can both be in row G but they are separated by R.
D is wrong because R can’t fit into row H, because he needs Q or S along with him.
E is wrong for the same reason D is.
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