For Z to have options in common with all cars apart from T, it must have S, because S is Y’s only option. The local diagram is drawn above.
Since Z now has S and L, then T must have P so that T and Z have no option in common.
A must be true.
B must be true.
C must be true. X, W, V and T all have P.
D must be false. Only Z, X and W have L. T can’t, because T needs P. D is CORRECT.
E must be true. Z, X, V and T all have S.
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