If S goes fifth, then O or T has to go fourth. They’re the only two pieces that can go beside O, and we need a link between 4 and 5.
Watch what happens if we put T in 4:
We have to put N in 2, and then we can link it with V in 1. But then O is left to go in 3. And O has no links with N or T. So this scenario doesn’t work.
So O has to go in 4. It’s pretty easy to place the rest. N and V share links, and T and N share links. Every combination works as long as we don’t put V in 1 and T in 2.
We can’t put N third. T would be in second, and V would be in first. But T and V don’t share a link. So A is wrong.
B is wrong because O has to be fourth. We saw that putting T fourth doesn’t work.
C is wrong for the same reason as B.
D is possible. N could go second, so V and N would link the first two spots. T could then go third, where it would be linked with N.
We don’t need a link between 3 and 4, because O and S are linked in 4 and 5. So every variable has a link with at least one of the pieces beside it, and D is CORRECT. It’s drawn below.
E is wrong because only N or T can go second.
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