LG Game 3 Question 13 Explanation, by LSATHacks
This question asks who has to run. This game is quite restricted: four out of five runners must run. So, if one runner is out, that means every other runner must be in.
A lot of the runners have restrictions that may be incompatible. So, in order to make valid placements, we want to keep the people with fewer restriction in. In fact, the right answer is probably the runner with the least restrictions.
T is easiest to place. Placing them doesn’t cause anything else to happen. So, T therefore might have to be in (because they’re easy to work with: things might be too difficult without them).
Let’s test to see if T is really essential. If we don’t have T, then we must have everyone else: Q, R, S, U.
Right away we can see this doesn’t work. If we have Q, we need T. So Q, R, S and U isn’t a possible combination.
D is CORRECT.
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