LSAT 65, Logic Game 2, Question 10, LSATHacks

If N is 6th, then there are only five spaces left for PST. Since these letters must be kept apart, their positions looks like this:

We can deduce a bit more. Rules 2 and 3 say that both S and T need a variable after them (S-O and T-W). So neither S nor T can go fifth.

Therefore P must go fifth. 

Once again there are two possibilities. Either S is first and T is third, or the opposite:

Next, apply rules 2 and 3. The 4th spot is the limiting spot in both cases. 

In the first diagram, W must go 4th to be after T.

In the second diagram, O must go 4th to be after S.

There’s only one spot left in each diagram, so put the other variables there. In the first diagram, O goes second:

In the second diagram, W goes second:

Once again, I’ve shown more deductions than we needed. We could have stopped with the very first deduction: P is 5th. B is CORRECT.

However, you never know which deduction will be tested. So it’s valuable to practice making all of them. Usually it doesn’t take long to add the extra deductions.

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