LG Game 3 Question 13 Explanation, by LSATHacks
I skipped this question the first time I did the game. I hoped later questions would give me scenarios that I could use to eliminate answers.
That didn’t end up helping much. So I came back and make scenarios to disprove wrong answer. Fortunately, with practice, you can learn to make correct scenarios quite quickly.
Try to disprove the wrong answers on your own first before you check my scenarios. Aim to do it correctly, and fast. If it feels slow, redo it until it’s quick and second nature.
This scenario eliminates A:
This scenario eliminates B:
This scenarios eliminates C:
The second scenario from the setup eliminates E. V can be out with W, since either N or V could be out:
D is CORRECT. It says P and O are out. You also have to put one of N/V out. That’s three variables.
But then you have to put W out, because PW are always in or out together. So P, O, W and one of N/V are out. You also have to put G out because the rules tell us that if G is in, O is in, and by way of the contrapositive we know that if O is out, G must be out.
That’s five variables out, which is too many. A maximum of three variables can be out.
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You can actually solve this problem quite quickly using the two scenarios in your main diagram, so long as you made sure to note the wild-card variables on the side.
A – The first scenario has F/G listed as both in and as an option on the side. T is listed on the side. Knowing that the F can be placed wherever eliminates the idea that one of the pair MUST be in.
B – Same as A, with F/G and O.
C – Kind of like A and B, but the first scenario has N/V listed as both out and as an option on the side. T is still listed on the side. The N and T can go wherever (i.e., both be out), there’s no necessity that at least one of them has to be in.
D – This is the correct answer. Scenario 1 has P listed as in, with O on the side. It doesn’t matter where O goes, since the necessary objective is already fulfilled. The almost fully accounted for Scenario 2 places O in and P out — they can’t move, so again, it fulfills the necessary condition that at least one must be in.
E – The second scenario has W on the listed as both. The V (in the N/V dual option) can either go in or out. So V and W can both be out.
Correct me if I made any mistake, but I hope this helps!
In answer choice D, five variables are actually out. P, 0, W and one of N/V are out, but G is also out because O is out. Remember those contrapositives! ;)
That’s correct. Thanks for catching that! The page has been updated.