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This question is a bit tricky. I almost got it wrong, because I mistakenly thought J could go fourth.
First, it’s obvious H and F can each go fourth. We’ve seen many scenarios that put them there.
Here’s one, just for proof. Remember that HF are reversible, so either could go fourth in this scenario:
So at least two students can go fourth: H and F.
G and K can’t go fourth, because they’re stuck earlier than HF. G and K can go third at the latest.
That leaves only J as a candidate.
The problem with putting J fourth is that it leaves no open spaces for HF to go beside each other. Have a look. Both G and K need to go before HF:
J leaves no space for HF. And if you put HF earlier than third, then there would be no way to put G and K in front of HF.
So B is CORRECT. Only H and F can go fourth.
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