This is an explanation of the second logic game from Section III of LSAT Preptest 66, the June 2012 LSAT.
A shopping center has a row of seven extra spaces (1, 2, 3, 4, 5, 6, 7). Seven businesses will be located in these extra spaces. The seven businesses are: an optometrist, a pharmacy, two restaurants, a shoe store, a toy store and a veterinarian (O, P, R, R, S, T, V). You will decide which business will be assigned to each space.
This is a linear game, but it’s complicated by the first rule. P and one of the R’s must be on either end of the diagram.
When a rule lets you draw something only two ways, it’s a very good idea to make two separate scenarios for your main diagram. This helps you visualize the game, and lets you draw separate deductions for each diagram.
Here are the first three rules. Draw it yourself while referencing the rules, then I’ll walk you through this diagram:
Here are the first three rules:
- P/R are at either end of the diagram.
- O/V must be beside P.
- And R can’t go in the two spots beside the first R.
Makes a simple diagram, right?
The final rule is that T/V can’t be together. Remember this rule well, it’s the only rule that can’t be shown on the diagram.
There are no rules for S, so S can go anywhere. I represent random variables with a circle:
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