LSAT 71, Logic Game 3, Question 14

Not much changes on this question. O is summarized, so whoever goes 3rd and 5th can’t be summarized. That’s all we know:

A and B are easy to eliminate. The diagram above shows that F can be first, and K can be sixth.

There are no summarization restrictions for these variables. A key to this game is that, except for N, you can always make a course not summarized.

C is CORRECT. It’s a little tricky to explain. Try drawing this yourself.

If F is summarized, it can only go first or second, since no summarized course can go beside O on this question. Let’s try placing F first. F is summarized, so the second course can’t be summarized:

You may see the problem. We must place N and T second and third. Neither position can be summarized here. But if N isn’t summarized, then T has to be summarized (rule 2). So this can’t work.

The same problem happens if you place F second. N is first and T is third. Both positions can’t be summarized, because they are beside F. But if N isn’t summarized, then T must be summarized. We are breaking a rule:

This next diagram proves that D and E are both possible, and therefore wrong:

LawHub Order

LawHub Order

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