LG Game 4 Question 21 Explanation, by LSATHacks
This question places tulips in bouquet one. You should ask what other rules that affects. Rule 5 says that if a bouquet has tulips, it needs peonies:
(Note: I’ve left off some “not” rules for simplicity. But you should be aware that, due to rule 1, bouquet three can’t have T or P, and bouquet 1 can’t have S. That’s what the double arrow with the X represents)
Rule 1 says that bouquets 1 and 3 don’t share flowers. So therefore bouquet 3 can’t have tulips or peonies:
Bouquet three now has a lot of restrictions. Whenever that happens, you should ask what variables can go in a group. S is already in bouquet 3, and T, P and L can’t go there. There are just five flowers, so only roses are left.
Bouquets 2 and 3 must share two flowers each. Bouquet 3‘s second flower can only be roses, and we must give the same two flowers to bouquet 2:
(The vertical line on group three is just a reminder that that group is full.)
The deduction that bouquets 2 and 3 need S and R answers the question. Only E has snapdragons and roses, therefore E is CORRECT. Just for the sake of completeness, this diagram proves that E is possible:
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Hi! Where would the lilies fit in for answer choice E? Or do the lilies not have to be used at all in the diagram?
Unless a rule specifically states something, it is not required. If it was required that every type of flower be used, either the set up or one of the rules would say something like “each type of flower must be used at least once.” Here, we are only told that the florist uses “one or more” of five types of flowers, which does not specify that each type must be used. Hope that helps!