LSAT 74, Logic Game 2, Question 10

In the setup, I explained that G and J must go third and fourth. That’s because both F and H need at least two lecturers after them.

So if G is with S, they must both go third or both go fourth. We can use this to make two scenarios. S and G go third, and J goes fourth, and then vice versa:

Scenario 1

Scenario 2

Next, we can fill in the existing rules. F–O–L take up three spaces, so there’s only one way to place them:

Scenario 1

Scenario 2

Then, only W and H are left to place, in the only open spaces.

Scenario 1

Scenario 2

A is CORRECT. In the second diagram, L can be third.

None of the other answers are possible in either diagram.

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