In the setup, I explained that G and J must go third and fourth. That’s because both F and H need at least two lecturers after them.
So if G is with S, they must both go third or both go fourth. We can use this to make two scenarios. S and G go third, and J goes fourth, and then vice versa:
Next, we can fill in the existing rules. F–O–L take up three spaces, so there’s only one way to place them:
Then, only W and H are left to place, in the only open spaces.
A is CORRECT. In the second diagram, L can be third.
None of the other answers are possible in either diagram.
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