This question places the walnut on lot three. When that happens, you should draw the hypothetical and combine it with the existing rules:
Rule two says that the maple is not with the walnut, so we can draw
M beside lot three. And rule three says that the larch or the walnut is in lot 1. Since the walnut is in lot 3, we must place the larch in lot 1.
Next let’s consider the fourth rule: the maple or the oak is planted in lot 2.
If we plant the oak there, then we need to plant the hickory, the oak, and one other tree. And the other tree can’t be the maple, because the oak and the maple can’t go together in lot 2 (rule four):
That means the maple would have to go in lot 1:
But this diagram doesn’t work. We have distributed spaces for seven trees, but lot 3 doesn’t have more than lot 1. This violates rule five.
So the hickory and the oak can’t go in lot 2. And thanks to rule five, there’s no space for them in lot 1 either. So we must place them in lot 3:
That also means we must place the maple in lot 2 in order to obey the fourth rule (maple or oak in lot 2).
Now we have the plum and the sycamore left to place. Lot 3 is full (rule 1) and so they can go in lots 1 or 2. Of course, at least one must go in lot 2, because lot one needs fewer trees than lot 3 (rule 5).
This is a could be true question, so either the plum or the sycamore in lot 1 or 2 will be the right answer.
A is CORRECT. The diagram above shows that all the other answers are impossible.
Note that these diagrams take a lot of words to explain, but they shouldn’t take that long to draw. This type of question can be solved fairly quickly, since your brain works without words. If these deductions took you a long time, then practice repeating them in order to learn to do the process faster.
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