LG Game 3 Question 13 Explanation, by LSATHacks
This question is unusual in that you can’t use a list of rules to eliminate answers. Instead you have to consider each scenario.
I found it easier to go answer by answer, see who got their first choice, and then check if the remaining choices make sense from that point.
This method eliminates two answers right off the bat: in A and C, nobody got their first choice. That violates the rules.
In D, Jackson gets their first choice. But then no one has their second choice (or better).
E is tricky. Jackson has their first choice. And Larabee has their second, so this looks good….except, Larabee could have had X, their first choice! So this answer isn’t consistent with the rules.
B is CORRECT. Larabee is first, Torillo is second, Jackson is third, Paulson is fourth.
The key to this question is realizing at setup that P/X and L/Y cant happen. Which not laws 3/5 answers.
I guess I read this question more than 100x but still cannot understand why alternative E is incorrect….
So for Jackson to get Y, he needs to go first. Z is Larabee’s second choice, which means that someone took his first choice, X. We’re told Paulson chose X, but that means that Y and Z both need to be taken since X his third choice.
Basically we’re in a situation where Larabee chose his second choice when his first choice is available; and Paulson chose his third choice when his second choice is available.
E shows Paulson with X, his third choice.
Paulson can never get X.
If X isn’t selected first, someone will select it second or Paulson will select Z second.
Likewise, Larabee can never get Y, it will always be gone by the second selection.