LSAT 80, Logic Game 4, Question 21, LSATHacks

To understand this explanation, you need to read the setup section. So do that if you haven’t yet. Here’s the setup diagram again:

In the setup, we saw that each group must have an ending value of six. Class 1 buildings are worth four, class 2 are worth two, and class 3 buildings are worth one.

In this question, Realprop now has three class two buildings. Which means, effectively, that they have taken all of Trustcorp’s buildings, and given away all of their own. (Technically, they could have L instead of one of Trustcorp’s buildings, but this doesn’t matter.)

So, we have to distribute the following between Southco and Trustcorp:

Note that L is arbitrary. It could instead be any of K, M or O, in which case Realprop would have L.

And the value of each group must be six. Clearly, the only way to do that is to give each group a class 1 building. You can’t put the two class 1’s together, or you’d have a value of eight.

So, the right answer will be either “Trustcorp has a class 1 building” or “Southco has a class 1 building”. A is CORRECT.

B and E are wrong because specific class 2 and class 1 buildings are interchangeable. So they can end up anywhere.

C and D amount to the same answer. In the group above, the two class 3 buildings and the one class 2 building are interchangeable. So, either Southco or Trustcorp could have them.

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