June 2007 LSAT, Logic Game 2, Question 10

Here’s the main diagram for reference:

This question places L three times. So, you should draw that. That means L will go last on Friday:

L also goes Thursday and Saturday. H must go last on Thursday (rule 1).

This question also says that H goes twice, and G goes once. That means we need one more H, and one G. So, one of them will go last on Saturday. The other will go on Thursday/Friday. (Thursday if it’s G, Friday if it’s H).

This question is asking who could go first on Thursday. It’s either G or L. So, D is CORRECT.