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LSAT Explanations › June 2007 LSAT Explanations (June 2007) › June 2007 LSAT Logic Games Explanations › Question 3

June 2007 LSAT, Logic Game 1, Question 3

June 2007 LSAT Explanations

LG Game 1 Question 3 Explanation

This question gives you a new rule. Whenever a question gives you a new rule, you should draw it, and see how it affects the existing rules.

June 2007 LSAT, Game 1, Question 3, Diagram 6

Here, 0 can’t go 3rd, and can’t go 5th. That means 0 must go 4th. C is CORRECT.

There are a few of things to point out.

Focus on restrictions

  • Once a variable gets many restrictions, you should consider where it can go. That’s how you get to the “0 must be 4th” deduction.
  • You should focus on 0, since it already has restrictions, and this question adds a new one.

Don’t draw, or draw a limited diagram

  • You don’t necessarily need to redraw the diagram. At an advanced level, you can just look at your setup and see “oh, this means 0 can’t go 1st, 2nd, 3rd and 5th”
  • But, you also don’t need to redraw a full main diagram. This is the diagram I actually drew on my own paper. It’s much faster and conveys the same information:

June 2007 LSAT, Game 1, Question 3, Diagram 7

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