LSAT 19, Logic Game 3, Question 15, LSATHacks

If F goes in boat 2 then there are three children in boat 1. It makes sense to re-use the scenario from question 14 and see if it helps on this question.

There is one other scenario that works. We could put F in boat 1 and both of the other adults, G and H, in boat 2. One of Z and X are in each boat and one of V and W are in each boat. Y will have to go in boat 1.

Now we look at both scenarios to see what could be true. Remember that we are looking for two people together in boat 2, not in boat 1.

A is wrong because when F is in boat 2, G is in boat 1.

B is wrong because G is in boat 2 in both scenarios whereas Y is in boat 1.

C could be true in the scenario when F is in boat 1 and H is in boat 2. V & W are interchangeable in that scenario. C is CORRECT.

D is wrong. V and W cannot both be together in boat 2 because there is no space.

E is wrong because Y must go in boat 1 in both scenarios.

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