LSAT 23, Logic Game 4, Question 22, LSATHacks

If R and S are the only ones that go first then they must also be the ones that go fifth.

S will go fifth on the first two meetings; R can’t because it is in first.

R will have to go fifth in the third meeting, when S is in first.

Remember, anyone who goes fifth has to go first somewhere else.

A can’t be true. R is the only one who can go fifth in meeting 3.

B can’t be true for the same reason. Putting anyone else fifth in meeting 3 would violate the rule that anyone speaking fifth must speak first somewhere else.

C can’t be true. S must always be either fifth or first.

D can’t be true. No one else can go fifth if we don’t put S there twice. R is in first in two places; R can only go fifth once. No one else can go fifth, because they would have to go first, too.

E is CORRECT.

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