LG Game 4 Question 24 Explanation, by LSATHacks
We know we have to put Q and R in first: everyone must go first or second at least once.
We have space to put one other person as well. I put in S, for the sake of example. But it could also have been T or U, or even Q or R again.
Q or R will have to go fifth at least once, during the time when S goes first (in my example). S can’t go first and fifth at the same time, and no other variable can go fifth.
Everything would work the same if we put S (or T, or U) in first in meeting 1 or 2. Q or R would have to go fifth at least during that meeting. No one else would be eligible, because anything that goes fifth has to go first too.
(Q/R actually have to go fifth twice. In my example no one else can go fifth in the first meeting, because S is in 2. But the answer choice only says “at least once”, which is also true)
A is CORRECT.
B could be true but doesn’t have to be. We can put anyone in first in one of the meetings, as long as Q and R each go once too.
C doesn’t have to be true. We could put S in first in the third meeting and have him go fifth in the second. (for example).
D and E are wrong because there is no reason why Q and R would have to speak third or fourth. No rule forces anyone to go third or fourth. Why should Q or R go there?
Leave a Reply