Always draw local rules. Put N in fourth and see what has to be true.
We know that L is somewhere before N. We can’t put L in second because O has to be one space away from L. So we can either put L first or third.
A is CORRECT. This diagram shows a scenario that works:
B is wrong. If we put L second, we have to put O two spaces away: in fourth. But M is fourth.
C is wrong. If we put M third then we would have to put P first. Then L could only go in 2. But we saw that doesn’t work: there’s no place to put O.
D is wrong. If O is in fifth, L is in third and then there is no place to put M. M can only go fifth or third.
E is wrong. If S is first then L would go in third. Then O would have to go in 5. Just like in D, there is no place to put M. M can only go third or fifth.
Note: we could have put L in 3 and O in first to make a workable scenario, but none of the answer choices asked us of that.
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