A is CORRECT. Here’s one way it could work:
B can’t work. If we only have one French novel then Russian novels will outnumber French novels.
C can’t work, because of rule 4. If you have both French plays, you lose the Russian play.
D can’t work, because the Russian novels would outnumber the French novels (rule 3). You can have four novels, at most (rule 2).
E violates the first rule.
Tom says
one of the conditions is “at least as many French novels as Russian novels are selected”, so 3 French novels need 3 Russian novels? I am really confused.
Tutor Lucas (LSAT Hacks) says
That rule just means that the number of French novels must be greater than or equal to the number of Russian novels. Another way to put it is that the number of French novels must be at least as great as the number of Russian novels.
So, if 2 Russian novels were selected, we’d need at least two French novels to be selected.
Member Will says
The answer is correct, but the rationale above is off. There can’t be four French novels. Let me know if I’m missing something.
Tutor Lucas (LSAT Hacks) says
Thanks for catching this Will. There are only three French novels total in the set, so the counter-example cannot select 4 French novels. That diagram should show 3 French novels, and one French play.
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