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LSAT Explanations » LSAT Preptest 33 » Logic Games » Question 10

LSAT 33, Logic Game 2, Question 10

LSAT 33 Explanations

LG Game 2 Question 10 Explanation

Here, you have to look for a relationship where one bird being in forces another bird out.

H and G are an example (but not the answer). If H is in, G is out.

LSAT PrepTest 33, Game 2, Question 10, Diagram 1

So look through your diagram looking for that type of symbol.

Luckily for us, the first answer is right. If J is in, W is out. This diagram shows it:

LSAT PrepTest 33, Game 2, Question 10, Diagram 2

A is CORRECT.

B is wrong. J and S can be together. One of them always has to be in, but they could both be in.

C is wrong. If W is in, S is in:

LSAT PrepTest 33, Game 2, Question 10, Diagram 3

D and E are wrong. There’s no rule connecting J and M or S and M. 

J and M are mentioned together in rule 2, but they have no effect on each other.

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Reader Interactions

Comments

  1. Tosin says

    August 13, 2015 at 10:12 am

    I fail to,understand how option B is wrong. the fifth rule says if jays are not on, then shrikes are. so how come they can be paired up together if the rule primarily says that when one is in the other is out? please expatiate!

    Reply
    • FounderGraeme Blake says

      August 25, 2015 at 4:10 pm

      Suppose I say: you’ll definitely eat soup or salad. We get:

      No soup –> Salad
      No salad –> Soup

      So we eat at least one. Can we eat both? Of course!

      You can only go left to right on conditional statements. These rule tell us what happens if we DON’T eat soup or DON’T eat salad. They don’t say what happens if we do.

      So the rule in our case was:

      No jays –> Shrikes
      No shrikes –> Jays

      The rule tells us what happens if one of the two is OUT. It gives us no rule for what happens if one of the birds is IN. For this type of rule, both can be in.

      Reply

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