We need to find the lowest number at Souderton. Let’s start with the diagram above. We definitely need one of O or J at S.
This eliminate A. We can’t have zero people at S.
Let’s try the diagrams. If we put P in R, then K, O and N are at S. Three people are at S. So E is wrong.
Let’s see if we can do better, and try Nr instead. That only causes 2 people to be in S.
We can’t get that number any lower. J has to be at S, because one of O/J has to be there. And if we moved P into R, we’d be in the scenario from the first diagram.
C is CORRECT. Two is the lowest number of doctors we can have at S.
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