LSAT 61, Logic Game 4, Question 19, LSATHacks

I initially skipped this question. I figured later questions would produce hypothetical scenarios that eliminate answers.

I was right. Question 20 eliminates B by saying J can go third.

This diagram from question 21 shows that J can go last, which eliminates E:

This diagram from question 22 shows that J can go second, which eliminates A:

(Just imagine M, J, L and F floating down onto the diagram in that order. It’s a legal combination.)

That leaves only C and D left to compare. That makes this a much easier question. Let’s try drawing J 5th and 6th.

First, draw J fifth, and M somewhere before J (rule 3):

Then, consider the biggest rule. Our combined diagram for rules 2 and 4 shows the order must be
L – F – GK. That’s hard to fit in; it needs four spaces. There are only four spaces before J, and M is already filling on one of them. So, we must put L and F before J, and GK after.

H would also have to go before J. But, this won’t work. H and M have to be two spaces apart (rule 1) and L can’t go second (rule 5). There’s no way to obey both of those rules. So C is CORRECT.

(Two spaces apart is 1st and 4th, which would force L – F into 2nd and 3rd. And, as I said, L can’t go 2nd.)

Let’s prove D can work, to be sure we haven’t made a mistake (When doing games under timed conditions, mistakes are easy.) We end up with this:

M goes before J thanks to rule 3. L – F – GK go before J because there’s no space to put GK after J. That leaves H to go after J, obeying rule one.

We just have to place the variables before J. This order works:

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