As with all local rule questions, you should draw the new rule on a diagram and see what it lets you figure out.
If T tests G on the second day then T must test H on the first day. The third rule says T has to test H at some point.
Next, we see where we can place YS. Y can’t test J, so YS must test F.
This also lets you know which bicycle Y tests on the second day. Only H and J are left. Y can’t test J, so Y must test H on the second day.
R and S both have to test a bike on day 1, so we have to place them in the only two days that are left. R tests G (because R tests J on day 2) and S tests J on day 1.
This lets us see that E is CORRECT. A–D not only don’t have to be true, they can’t be true.
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