As with all local rule questions, you should draw the new rule on a diagram and see what it lets you figure out.

If T tests G on the second day then T must test H on the first day. The third rule says T has to test H at some point.

Next, we see where we can place YS. Y can’t test J, so YS must test F.

This also lets you know which bicycle Y tests on the second day. Only H and J are left. Y can’t test J, so Y must test H on the second day.

R and S both have to test a bike on day 1, so we have to place them in the only two days that are left. R tests G (because R tests J on day 2) and S tests J on day 1.

This lets us see that **E** is **CORRECT.** A–D not only don’t have to be true, they can’t be true.

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Britt says

Nvm Got it, cannot have two ‘T’s on the second day! That took all of 5 hours!

Avi says

Graeme-

Confused about one point. For Preptest 64, game 3, Q. 14, You wrote: “If T tests G on the second day then T must test H on the first day. The third rule says T has to test H at some point.”

I don’t see at all the conclusion that T must test H on the first day. why not on the second day? Trying to make sense of it all!

Britt says

I have this same question right now and i cannot seem to see where i misread

Avi says

wait – nevermind – I misread. Good stuff!