LSATHacks
  • Explanations
  • Tutoring
  • Courses
  • Login
  • Cart
  • Explanations
  • Tutoring
  • Courses
  • Login
  • Cart
LSAT Explanations › Preptest 134 › Logical Reasoning › Question 20

LSAT 134 | Section 1 | Logical Reasoning: Q20

LSAT Preptest 134 explanations

LR Question 20 Explanation

QUESTION TEXT: Members of the VideoKing Frequent Viewers club…

QUESTION TYPE: Must Be True

FACTS:

  1. Member + more than ten ➞ coupon only at your local store.
  2. Member + fewer than ten ➞ coupon only at the Main Street store.
  3. Pat has rented less than ten movies and can get a coupon at a local store (Walnut Street, which is not Main Street)

ANALYSIS: Pat rented fewer than ten movies. If Pat were a member, she could only get coupons at the main street store.

Since Pat can get coupons elsewhere, she must not be a member. This is the contrapositive of fact #2 above: Can get coupons elsewhere ➞ Member or ten or more movies.

Since Pat is not a member, we can say “some people” (i.e. Pat, at least) can get a coupon even if they aren’t members. One or more = some. Why can Pat get coupons even if she isn’t a member? Maybe it’s a special promotion to get people to sign up.

___________

  1. The stimulus never says anything about non-members. Maybe they can get coupons at all stores (as a special promotion, for example).
  2. We know from the stimulus that Pat is not a member. So we don’t know anything about individual members. Maybe they all rent more than ten movies. The second fact tells us what happens if someone rents fewer than ten movies. But that doesn’t mean anyone actually does.
  3. We only have Pat’s example, and she isn’t a member. We don’t know about any members.
  4. CORRECT. If Pat were a member, she would have to get her coupon at Main street, as she’s rented fewer than ten movies. Since she gets her coupon at Walnut street, she must not be a member. And since she can get a coupon, that means at least “some” people can. “Some” can be as few as one.
  5. Who knows? Pat isn’t a member, so maybe she can get a coupon anywhere. Lots of stores will let you get a discount in exchange for signing up to be a member of their program.
Previous Question
↑ Return to PT 134
Next Question

More Resources for Must Be True Questions

  • Conditional Reasoning Article: Learn about conditional statements on the LSAT.
  • LR Diagrams Guide: Learn how to draw LR diagrams.
  • Intro to Conditional Reasoning: This intro course lesson covers conditional reasoning basics.
  • Intro Course lesson: This intro course lesson covers Must Be True questions.
  • Mastery Seminar lesson: This LR Mastery seminar lesson covers must be true questions.
Quick Jump PT Section Que

Hi, I'm Graeme Blake

I scored a 177 on the LSAT. I founded LSATHacks and created the LSAT Mastery Seminars to help students succeed.

I’ve personally written explanations for 5,000+ LSAT questions. If you find these explanations helpful, you'll definitely like our courses.

Join my email list for LSAT study tips and resources.

Comments

  1. Alex Richards says

    April 8, 2020 at 9:47 am

    It seems like its worth pointing out how the kind of tricks the LSAT uses to see how focused on logic you are. I get the contrapositive explanation, but it violates common sense: non-members have greater access to the discount than members do.

    Reply
    • Graeme Blake says Founder

      January 26, 2024 at 8:32 pm

      It’s a fair point. Though I would counter that oftentimes non-members get perks members don’t have. Once you’re a member the company already has your business. Whereas signup bonuses for new members are frequent offers for many services such as credit cards, cellphone plans, online poker, etc.

      Outside knowledge on the LSAT can be dangerous. If everyone agrees, it is reasonable to make an assumption. But you have to think about whether something is *truly* a universal belief vs. just your own belief.

      Note: This is an old comment but I wanted to clarify the point.

      Reply
  2. Arman says

    February 29, 2020 at 2:12 pm

    If the stimulus does not clarify that Pat is a member, do we assume that they are not?

    Reply
    • Graeme Blake says Founder

      January 26, 2024 at 8:33 pm

      No, you can’t just assume they are not. Rather, the deduction that they are not follows from the logic above. Pat’s circumstances violate the rules for members, so we can conclude she is not a member.

      Note: This is an old comment but I wanted to clarify the point.

      Reply

Leave a Reply Cancel reply

Your email address will not be published. Required fields are marked *

Free LSAT Email Course

My best LSAT tips, straight to your inbox

Increase Your Score

LSATHacks Courses Aiming For The 170S? See exactly how a top scorer thinks INCREASE YOUR SCORE
“The seminars teach you how to think like a high-scorer so that you can choose the correct answer quickly.” — Jay
“Not only did my score improve but I was able to approach LR with utter confidence” — Kacie L.

Resources

  • Articles
  • Blog
  • Free Email Course
  • LSAT Preptest Converter
  • Experimental Section Checker
  • LSAT Prep Books

About LSATHacks

  • About/Contact
  • Courses
  • Free Trial

Community

  • Discord
  • Social Media
  • Webinars
Disclaimer: Use of these explanations requires official LSAT preptests. LSAT is a registered trademark of LSAC.
LSAC does not review or endorse specific test preparation materials or services and has not reviewed this site.

© Copyright 2026 LSATHacks. All Rights Reserved. | Privacy | Terms