LSAT 78, Logic Game 1, Question 4, LSATHacks

This question places T out. This also means S is out (rule 2). You can draw that on the list of all variables:

Next think about who is the most restricted variable. This is always important on logic games. W is the most restricted. 

If W is in, R and V are out. This only leaves QWX.

So that’s one possibility. What about if W is out? Then QRVX are left. We can only have one of Q and R (because they must be leader, rule 1), so we need to have Q/R + VX.

Either way, X must be in. E is CORRECT.

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Note: This is exactly how I solved this question in timed conditions. I first drew:

I figured out what happened if W was in by looking at the list (And visualizing R and V being out, since I had memorized rule 3). I wrote down the list of what’s left, QWX.

Having considered what happens if W is in, I then considered what happens if W is out by crossing it out.

I then figured out Q/R + VX were necessary, by seeing who was left, and remembering rule 1. 

This is the same process I described in the explanation above, but I wanted to show you the steps + diagrams I used in their real-time order.

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