LG Game 4 Question 22 Explanation, by LSATHacks
To solve a “completely determined” question, you should look for the variable that’s in the most rules. It stands the best chance of affecting other things.
Here’s the setup for reference:
You can see that T is in both rules above. So, as we saw in question 20, if T doesn’t transmit to Q or P, we can make two deductions:
- R transmits to Q
- U transfers to P
So, T is a promising candidate. Only B and C mention T. And B is not good: it has T transmit to Q. That means we only get one additional deduction.
Picking the answer that says T to Q means we only know two things: T to Q, U to P
But in C, where T transfers to S, we know three three: T to S, R to Q, U to P. So, let’s try C:
I’ve drawn the two additional deductions to the right. Let’s fit them on the diagram. Q obviously attaches to R. As for U – P, we need to put something after S, so U goes there:
So, C is CORRECT.
Why doesn’t E work for for PT 79, Sec 3, Que 23?
And I just realized my mistake. Please disregard. Thanks!
Hi Graeme,
Quick question for you! I understand how you got to the T-S-U-P set up; however, I am unsure how this doesn’t break the T/U->P rule? Does this mean that T or U does not have to directly transmit to P, but that T/U simply must be earlier in the sequence?
I thought that only one computer can be infected after S so how can the S-U-P (answer choice C) option be correct?