LSAT 80, Logic Game 2, Question 8, LSATHacks

We know that U and X go beside each other, in either order. This question places U third, so we can make one diagram with X 2nd and another with X fourth:

I added in the rule that X and W can’t be beside each other (rule 4). 

Next, you should see how to place T _ _ W, since they’re the most restrictive element. Normally, T can only go in 2, 3 or 4.

The second diagram actually doesn’t work at all. If we place T 2nd, then W would have to go fifth in order to be two spaces apart from T. But that doesn’t work, as W and X can’t be together (rule 4)

So, we’re left with the first diagram. In that one, we have to place T fourth:

Only R, and SZ are left to place. SZ can’t go together, so one goes 1st, and the other goes in 5 or 6 with R:

This maps out the only possibilities, so now we can simply pick the right answer from the diagram. 

B is CORRECT. All the other answers contradict the diagram.

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