LSAT 81, Logic Game 3, Question 13, LSATHacks

If T is first, we can make two diagrams. One with S third, and one with S 4th (rule 1):

The second diagram doesn’t work. In the setup I mentioned that having two blocs of two open spaces will force WZ to go in one, and RV in the other. This doesn’t work, because RV can’t be beside each other. So, we’re in scenario 1.

RV and WZ are left to place. Since RV must be separate, we can put one of RV second, and the other after S with WZ:

Though this is more work than we had to do. Just knowing S is 3rd is enough: C is CORRECT. Whenever you make a major deduction such as “S can’t go fourth”, it’s a good idea to stop and check if that answers the question. (S can only go 3rd or 4th in this game, so “S not 4th” = “S 3rd”)

The other answers are all things that could be true in the scenario above, but don’t have to be. 

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